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2 years ago

Help please!!!!!11!!!1!!

Mathematics

1 answer:

dedylja [7]2 years ago

8 0

Answer:

2.1 meters

Step-by-step explanation:

$13.8=2w+2(w+2.7)$

$13.8=2w+2w+5.4$

$13.8=4w+5.4$

$8.4=4w$

$2.1=w$

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A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70% of the time when t

V125BC [204]

We're told that

$P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995$

$P(B\mid A)=0.7$

$P(B\mid A^C)=0.05$

a. We want to find $P(A\mid B)$ . By definition of conditional probability,

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}$

By the law of total probability,

$P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)$

Then

$P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657$

(the first equality is Bayes' theorem)

b. We want to find $P(A^C\mid B^C)$ .

$P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984$

since $P(B^C\mid A^C)=1-P(B\mid A^C)$ .

4 0

3 years ago

What is greater 27% or 0.48

mylen [45]

Well since 27% in decimal form is .27, that mean .48 is greater.

27% < 0.48

3 0

2 years ago

PLEASE ANSWER!!!!! IN A PARAGRAPH

nadya68 [22]

Answer:The United States Electoral College is the group of presidential electors required by the ... They choose one elector per district and two electors for the ticket with the ... on the count of both voter and non-voter residents for state apportionment. ... there can be a president elected who does not win the national popular vote.

Step-by-step explanation:

3 0

2 years ago

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(5,0) is a solution to the equation y = 5x + 5 Question 11 options: True False

Keith_Richards [23]

Answer:

False

Step-by-step explanation:

y=5x + 5

0=5 (5)+5

0=10+5

0≠15

False

5 0

3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

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1 year ago

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