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2 years ago

2 short questions Please help

Mathematics

2 answers:

Mila [183]2 years ago

5 0

Answer:

b c = 5.25p this is the answer

horrorfan [7]2 years ago

5 0

For the first problem shown the answer is number B.

It is B because we our always going up by $5.25

For our second one it isn't a function,

it isn't a function because it follows the same rule through-out it besides at the end of it.

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I need help because I didn't understand and I don't know how to do and I don't know plz help me and if you help me I would like

zepelin [54]

Umm what do you need helo with?

3 0

3 years ago

Jada has 60% of her goal of $60 saved for her trip. If 10% x 6 = 60%, how much money does Jada have saved

Murljashka [212]

Jada has saved 60% of $60. This is a percent of number question.

First we need to know 60% of $60

Change the percent to a decimal and multiply.

.60(60) =$36 saved so far.

8 0

3 years ago

Read 2 more answers

An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"

7nadin3 [17]

Answer:

B: a = 1, b= 7, c = -2

Explanation:

$\sf Quadratic \ Equation : \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a}$

Knowing This:

solve for b

-b = -7

b = 7

solve for a:

2a = 2

a = 1

solve c:

b² - 4ac = 57

7² - 4(1)(c) = 57

-4c = 57 - 49

-4c = 8

c = 8/-4 = -2

4 0

1 year ago

Read 2 more answers

ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

$EF = \sqrt{(49) + (16)}$

$EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\$

Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

$GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8$

Thus we could see that the sides EF = FG

So it is a isosceles triangle.

6 0

2 years ago

What is the rate of change of the linear relationship modeled in the table (-2,5) (-1,4) (0,3) (1,2)

poizon [28]

The rate of change of the linear relationship is -1.

Explanation:

It is given that there is a linear relationship between all these points, these points lie on a straight line.

The equation to find the slope passing through two points $\left(x_{1}, y_{1}\right)$ and $\left(x_{2}, y_{2}\right)$ is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting the points $(-2,5)$ and $(-1,4)$ , we get,

$\begin{aligned}m &=\frac{4-5}{-1+2} \\&=\frac{-1}{1} \\&=-1\end{aligned}$

Thus, the slope is -1.

Thus, the rate of change of the linear relationship is -1.

8 0

3 years ago