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olga55 [171]
2 years ago
15

1+1= I need help please I am just seeing if this app really work

Mathematics
1 answer:
STatiana [176]2 years ago
8 0

Answer:

1+1=2

Step-by-step explanation:

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Find dy/dx of y=csc(square root of x)
Vitek1552 [10]

Answer:

y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}

Step-by-step explanation:

y = csc x

y' = -cot x csc x

y = \csc \sqrt{x}

y' = \dfrac{d}{dx} [\csc \sqrt{x}]

y' = (-\cot x \csc x) \dfrac{d}{dx} \sqrt{x}

y' = (-\cot x \csc x) \dfrac{d}{dx} x^{\frac{1}{2}}

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Answer:

Horizontal Asymptote:    y=2

Vertical Asymptote: x=3

Step-by-step explanation:

One way: Look at graph

Look at for a horizontal or vertical line that both lines don't touch.

Second Way:

When you look for vertical asymptotes, you set the denominator equal to zero and solve.

For example, the second question has a denominator of x-3.

x-3=0

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When you look for horizontal asymptote, you do long division.

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The answer will be 2. 2 is the quotient. You only want quotient not remainder.

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Think:  You're treating the numerator and the denom. in precisely the same way.  In doing so you are NOT changing the value of the fraction, only the appearance.

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2/3 and 14/21 result in precisely the same decimal fraction, showing that the latter set of fractions is equivalent to the former set.

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Answer:

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The two arrows on the ends of the line (pointing upwards and downwards respectively) indicate that the function goes in those direction for infinity. Therefore, if there are an infinite amount of y-values, the range is (-∞, ∞).

While the slope is quite steep, there is still a slope and slowly "expands" the line on the horizontal axis. Because there is no limit to the y-values, the domain will also expand infinitely. Therefore, the domain is also (-∞, ∞).

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