Answer: C < B < A
<u>Step-by-step explanation:</u>
First, let's evaluate the growth rate of A from [1, 3]

= 300
coordinate is (1, 300)

= 675
coordinate is (3, 675)
Average growth rate (AGR) is: 
AGR (A) = 187.5
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Next, let's evaluate the growth rate of B from [1, 3]
The coordinates are already provided as (1, 120) and (3, 480)
Average growth rate (AGR) is: 
AGR (B) = 180
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Lastly, let's evaluate the growth rate of C from [1, 3]
f(x) = 600(1.2)ˣ
f(x) = 600(1.2)¹
= 720
coordinate is (1, 720)
f(x) = 600(1.2)³
= 1036.8
coordinate is (3, 1036.8)
Average growth rate (AGR) is: 
AGR (C) = 158.4
+2 crosses the equal sign to become 4y=18-2,as 18-2=16 so you get 4y=16 and finally divide both sides by 4,as 4 goes into 16,4 times,therefore,y=4
<span>5ab^2 + 10ab
5ab^2 = 5ab *(b)
10ab = 5ab *(2)
so GCF of </span>5ab^2 + 10ab = 5ab
400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$