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Neko [114]
3 years ago
13

Please help, I will mark you as brainliest. Please help, use the Pythagorean theorem to find the apothem of a regular hexagon wi

th a side length of 8

Mathematics
1 answer:
Musya8 [376]3 years ago
6 0

Answer:

1.755

Step-by-step explanation:

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Transform the polar equation to a Cartesian (rectangular) equation: r= 4sinθ
sweet-ann [11.9K]

Answer:

  x^2 +y^2 = 4y

Step-by-step explanation:

Using the usual translation relations, we have ...

  r^2 = x^2+y^2

  x = r·cos(θ)

  y = r·sin(θ)

Substituting for sin(θ) the equation becomes ...

  r = 4sin(θ)

  r = 4(y/r)

  r^2 = 4y

Then, substituting for r^2 we get ...

  x^2 +y^2 = 4y . . . . . matches the first choice

8 0
3 years ago
I need help with my math homework, the thing we are working on is Unit Rates. Please help me.
lesantik [10]
I can help too yo, just post the questions and stuff like that


6 0
3 years ago
Could someone please help!
Misha Larkins [42]

Answer: t = -1

Step-by-step explanation:

8 0
3 years ago
Help please !! geometry problems.
Akimi4 [234]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

In each question sum the 3 angles and equate to 180

3

a.

x + 8x + 90 = 180

9x + 90 = 180 ( subtract 90 from both sides )

9x = 90 ( divide both sides by 9 )

x = 10

b

4x - 5 + 3x + 11 + 90 = 180

7x + 96 = 180 ( subtract 96 from both sides )

7x = 84 ( divide both sides by 7 )

x = 12

4.

4x + 2x + 11 + 19 = 180

6x + 30 = 180 ( subtract 30 from both sides )

6x = 150 ( divide both sides by 6 )

x = 25

5.

5x + 20 + 2x - 5 + 3x - 10 = 180

10x + 5 = 180 ( subtract 5 from both sides )

10x = 175 ( divide both sides by 10 )

x = 17.5

3 0
3 years ago
Please Help<br><br> If y = 12, then 3y^2 - 5 =
vredina [299]

Step-by-step explanation:

if y = 12

than a/q

= 3(12)² - 5

→ 3 × 144 - 5

= 432 - 5

→ 427 ans

<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> </u></em><em><u>dear</u></em><em><u> take</u></em><em><u> care</u></em><em><u>!</u></em>

4 0
3 years ago
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