Answer:
8/9 of the course are males.
Easy
the easiest way is to imagine that you have a rectangle with a corner cut off
the area of the figure=area of rectangle-area cut off
area that was cut off was a triangle
area of rectangle=length times width
area of triangle=1/2base times height
so we draw imaginary lines like in attachment
find area of rectangle
legnth=9 inch
width=9 inch
area=9 times 9=81 in^2
triangle
the top part is ?+5=9, so the base of triangle=4
the side is ?+4=9, so the base is 5
area=1/2 times 4 times 5=10 in^2
area=rectangle-triangle
area=81-10=71 in^2
V^2/(1-v^2/c^2)=R
v^2=R(1-v^2/c^2)
v^2=R-Rv^2/c^2
v^2-Rv^2/c^2=R
v^2(1-R/c^2)=R
v=sqrt(R/(1-R/c^2))
where R was original right side, dont forget plus minus
Normally I'd love to help, but put in a picture. I'm confused.
Answer:
Step-by-step explanation:
and also you are diviing the numbers then subtracting 9