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3 years ago

From 145 pounds to 132 pound percent decrease

Mathematics

2 answers:

Airida [17]3 years ago

3 0

145-132= 13

13/145 = 0.089655 rounded to 9

9%

Finger [1]3 years ago

3 0

Your answer is 9%

Hope this helps =)

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AC = Round your answer to the nearest hundredth. 5 ? 35 B

Bingel [31]

Answer:2.87

Step-by-step explanation:sin =opp/hyp

Sin 35=ac/5

Cross multiply

Sin 35 x 5 = ac

0.5736 x 5 =ac

2.868=ac

Ac=2.87

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3 years ago

the basketball court in the park is rectangle two of the sides are 84 feet long and the other two sides are 50 ft long what is t

butalik [34]

Hello!

So, we know that the length of the rectangular basketball court is 84 ft, and the width is 50 ft.

The formula for perimeter of a rectangle is:

P = 2l + 2w

This means that we need to multiply the length by two and the width by two as well.

Substitute:

P = 2(84) + 2(50)

P = 168 + 100

P = 268 ft

ANSWER:

The perimeter of the basketball court is 268 feet long.

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3 years ago

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Anettt [7]

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3 years ago

Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2

soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

Solution:

Given that line is passing through point (-5, 2) and (3, r)

Slope of the line is $\frac{-1}{2}$

Need to determine value of r.

Slope of a line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by following formula:

$\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ --- eqn 1

$\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}$

On substituting the given value in (1) we get

$\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}$

Hence the value of "r" is -2

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What is 7035 divided by 38??

alexdok [17]

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