Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
If you think of the equation as an equation for a line.
y=mx+b
y
=
m
x
+
b
where
C=5/9(F−32)
C
=
5
/
9
(
F
−
32
)
or
C=5/9F−5/9(32)
Answer:
B
Step-by-step explanation:
edge2020
Answer:
Where is the table?
Step-by-step explanation:
2(i<3u) is the answer to your problem