The question given is incomplete, I googled and got the complete question as below:
You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from over-fishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day. Use these data to address the following questions. Show your work.
a. What is the probability that your last pot will have the necessary 7 crabs?
b. What is the probability that your last pot will be empty?
Answer:
a. Probability = 0.0083
b. Probability = 0.0907
Step-by-step explanation:
This is Poisson distribution with parameter λ=2.4
a)
The probability that your last pot will have the necessary 7 crabs is calculated below:
P(X=7)= {e-2.4*2.47/7!} = 0.0083
b)
The probability that your last pot will be empty is calculated as:
P(X=0)= {e-2.4*2.40/0!} = 0.0907
Answer:
Option (3). EF
Step-by-step explanation:
From the figure attached,
Plane defined by EAB can be represented by the face EABF of the square prism also.
Similarly, plane EFG can be represented by the face EFGH of the prism.
Now these sides EABF and EFGH are joining each other at the edge EF of the cuboid.
Therefore, intersection of the given planes is EF.
Option (3) will be the answer.
Answer:
5.7
Step-by-step explanation:
<u>unrelated</u>, I love how peter is open about buying makeup. i feel as if the gender roles are garbage. #YasQueen #GoPeter #PeterIsCool #MakeupCanBeForBoysToo <3
(also peter could totally be a girl and I am misgendered a person)
Answer:0
The can will have no value after 5 years
Step-by-step explanation:
If it lost 20% value in the first year after 5 year is amount to 100% devalued making it worth nothing at the fifth year.
20/100*24000=$4,800 in the first year
After the first year the value will be
Therefore in five year the value will be
4800*5= $24000 devalued
Making the car zero worth
30 animals on Wednesday =
22 cats x $3.50 per day = $75
8 birds x $1.00 =$8
$75 + $8 = $85
# of birds @ the shelter = 8
# of cats @ the shelter = 22