x=-3 then y= 27
x= -2 then y= 9
x=2 then y: 
x=3 then y: 
The graph of the function decreases from left to right.
Option C is correct.
Step-by-step explanation:
We are given the function: 
and we need to fill the table
if x = -3 then y=?
Putting value of x in the given function:


Applying exponent rule a^-b= 1/a^b

if x = -2 then y=?
Putting value of x in the given function:


Applying exponent rule a^-b= 1/a^b

if x = 2 then y=?
Putting value of x in the given function:


Applying exponent rule a^-b= 1/a^b

if x = 3 then y=?
Putting value of x in the given function:


Applying exponent rule a^-b= 1/a^b

So, x=-3 then y= 27
x= -2 then y= 9
x=2 then y: 
x=3 then y: 
Graph of the function is shown in figure attached.
The graph of the function decreases from left to right.
Option C is correct.
Keywords: Solving Equations
Learn more about Solving Equations at:
#learnwithBrainly
Answer:
x+3y = 6
or, x = 6-3y.................(1)
3x+5y =6..........(2)
Substituting x = 6-3y in equation (2),
3 (6 - 3 y)+5 y =6
or, 18 - 9y +5y=6
or, y = 3
x = 6 - 3y = 6- 3.-3 = -3
Answer:
Step-by-step explanation:
18/6=51/p
do cross multiplication
6*51=p*18
306/18=p
17=p
therefore perimeter is 17 cm
Ladder forms a right triangle with base 7 and hypotenuse 12, so
7²+h²=12². where h is the height
49+h²=144
h²=91
h=√91 or about 9.5
ladder touched the building about 9.5 ft up
Answer:
x= -1/23
Step-by-step explanation: