When you line the object up against the ruler you are measuring it's side, if you put it on the one instead of the zero then you're making the object one inch longer, so you'd have to subtract the one in the end
Answer:
You are given such data:
In the 12th grade total of 48 students, only 13 students participate in at least one extracurricular activity and 48 - 13 = 35 students do not participate.
In 11th grade total of 106 - 48 = 58 students, 37 students participate in at least one extracurricular activity and 58 - 37 = 21 students do not participate.
<em>good luck, i hope this helps :)
</em>
If you plug in 1 for x, you get f(1) = 1^1, so it is just 1.
The answer is: " 53 
% " .
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→ " 53 % " of 75 is "40" .
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Explanation:
To solve:
* 75 = 40 ;
→ Rewrite as:
* 
= 40 ;
→ The "100" cancels to "4" ; and the "75" cancels to "3" ;
→ {since: "{100 ÷ 25 = 4}" ; and since: "{75 ÷ 25 = 3"} ;
→ So; we rewrite the problem as:
→ 
* 
= 40 ;
→ which is:
* 3 = 40 ;
→ Divide each side of the equation by "3" ;
* 3 ÷ 3 = 40 ÷ 3 ;
to get:
→ = 
;
Now, cross-multiply:
→ 3x = (4)*(40) ;
→ 3x = 160 ;
Divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 160 / 3 ;
to get:
→ x = 53 .
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Answer:
1) x = 40° & y = 50°
2) x = 100° & y = 80°
Step-by-step explanation:
1)
ABCD is a cyclic quadrilateral (∵ all the vertices of the quadrilateral are touching on the circle). As it is a cyclic quadrilateral , sum of it's opposite angles will be 180°.
⇒ ∠ADC + ∠ABC = 180°
⇒ 130° + y = 180°
⇒ y = 180 - 130 = 50°
In ΔABC ,
∠ACB = 90° (∵ AB is the diameter of the circle and a diameter subtends an angle of 90° on any point on circle.)
Using angle sum property of triangle ,
∠ABC + ∠ACB + ∠CAB = 180°
⇒ y + 90° + x = 180°
⇒ x + 50° + 90° = 180°
⇒ x + 140° = 180°
⇒ x = 180 - 140 = 40°
2)
ΔABC is an isosceles triangle (∵AB = AC). As it is an isosceles triangle , it's base angles will be equal. So , ∠ABC = ∠ACB = 50°
Using angle sum property of triangle ,
∠ABC + ∠ACB + ∠BAC = 180°
⇒ 50° + 50° + y = 180°
⇒ y + 100° = 180°
⇒ y = 180 - 100 = 80°
ABEC is a cyclic quadrilateral (∵ all the vertices of the quadrilateral are on the circle.). As it is a cyclic quadrilateral , sum of it's opposite angles will be 180°.
⇒ ∠BAC + ∠BEC = 180°
⇒ y + x = 180°
⇒ x + 80° = 180°
⇒ x = 180 - 80 = 100°
