answer: 32, 72
question 6
angle PQR and 148 are supplementary angles, so they add up to 180
PQR + 148 = 180
PQR = 180 - 148 = 32
question 7
in triangle RTS, all three angles must add up to 180
angle R = angle PQR = 32
angle S = 180 - 104 = 76 (because of supplementary angles)
angle T = angle RTS (we need to find this)
32 + 76 + angle RTS = 180
angle RTS = 72
A and B lie on the line, yes, but what specifically are you supposed to do? Looks like your problem statement was cut off before you'd finished typing it in.
You say your line passes thru (-2,5) and has a slope of 2/3? Then, using the point-slope formula,
y-5 = (2/3)(x+2) This is the general equation for your line.
Now let's play around with B(-2,y). Suppose we subst. the x-coordinate of B, which is -2, into the equation y-5 = (2/3)(x+2); we get y-5 = (2/3)(-2+2) = 0. This tells us that y must be 5. But we already knew that!!
So, please review the original problems with its instructions and this discussion and tell me what you need to know from this point on.
<h3>
Answer: 2x^2 + 6x - 4</h3>
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Work Shown:
f(x) - g(x) = [ f(x) ] - [ g(x) ]
f(x) - g(x) = ( 3x^2+x-3) - ( x^2-5x+1 )
f(x) - g(x) = 3x^2+x-3 - x^2+5x-1
f(x) - g(x) = (3x^2-x^2) + (x+5x) + (-3-1)
f(x) - g(x) = 2x^2 + 6x - 4
From top to bottom: 16, 5, 28. Please give me 'brainliest answer?
