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il63 [147K]
3 years ago
10

I need help on this ASAP!!

Mathematics
1 answer:
vazorg [7]3 years ago
7 0
The answer is 16 units
An easy way to find the perimeter is remembering the formula of a+b+c.
So in this case, you count how many units each line of the triangle it covers. 4+6+6= 16
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A set of equations is given below:
ipn [44]
The correct answer is 'Equation F can be written as 2d + 1 = 3d + 7'. In order to find the answer to a system of equations, the two equations must be set equal to each other. For instance, if we had the equations x = y + 1 and x = 3y - 1, we would set the two equations equal to one another to find the answer.

x = y + 1
x = 3y - 1
y + 1 = 3y - 1
1 = 2y - 1
2 = 2y
1 = y

x = y + 1
x = 1 + 1
<span>x = 2

We can use this to solve the set of equations above.

</span><span>2d + 1 = 3d + 7
</span>1 = d + 7
-6 = d

c = 2d + 1
c = 2(-6) + 1
c = -12 + 1
c = -11

Hope this helps!
6 0
3 years ago
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Which equation gives the line shown on the graph?
SVEN [57.7K]

y = ½ x + 4

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4 0
3 years ago
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OleMash [197]

Answer:

X=3

Step-by-step explanation:

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4 0
2 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
PLEASE HELP ME 100 POINTS
Ghella [55]

Answer:

b

Step-by-step explanation:

b b b b b b b   b bb b b b b bb b b bb b bb bb   bb b bb b b b b b b b b bb b b  b  b bb b  bb b b b b  bb b b b b b b  b bb  bb

5 0
3 years ago
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