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3 years ago

I need help on this ASAP!!

Mathematics

1 answer:

vazorg [7]3 years ago

7 0

The answer is 16 units
An easy way to find the perimeter is remembering the formula of a+b+c.
So in this case, you count how many units each line of the triangle it covers. 4+6+6= 16

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a cone shaped container has a height of 9 inches and a diameter or 2in it is filled with a liquid that is worth $2 per cubic inc

Mice21 [21]

Answer:

$18.84

Step-by-step explanation:

The area of a cone is (1/3)pi*r^2*h

With all variables plugged in we get an area of (1/3)*3.14*(1^2)*9, or 9.42 cubic inches. With a value of 2$/in^3, we get 2*9.42, or 18.84.

Therefore, the value of the container is $18.84.

5 0

3 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

3 years ago

Find the value of x. 10_3

Lisa [10]

$67^o;\ 90^o\ and\ x^o\\angles\ on\ one\ side\ of\ a\ straight\ line\\will\ always\ add\ to\ 180^o.\\\\67^o+90^o+x^o=180^o\\157^o+x^o=180^o\ \ \ \ |subtract\ 157^o\ from\ both\ sides\\\boxed{x^o=23^o}$

3 0

3 years ago

Explain how you would distribute 4 ones into 5 groups.m

jenyasd209 [6]

Answer:

Step-by-step explanation:

bvfghhgf

7 0

3 years ago

Two boats left a base camp at bearing of S60°E and S50°W at speeds of 50km/h and 70km/h respectively. Find the distance between

ivolga24 [154]

Answer:

197.93 km

Step-by-step explanation:

Let the base camp is point A and boats' locations after two hours are points B and C.

By connecting the three points together we get a triangle ABC with sides:

AB = 50*2 = 100 km
AC = 70*2 = 140 km

The angle between AB and AC is:

60 + 50 = 110 degrees (opposite directions from south)

We are looking for the distance BC, which can be found by using the law of cosines:

BC² = AB² + AC² - 2AB*AC*cos ∠BAC

BC² = 100² + 140² - 2*100*140*cos 110°
BC² = 39176.56 (rounded)
BC = √39176.56 = 197.93 km (rounded)

The distance between the boats is 197.93 km.

7 0

2 years ago