Answer:
Hence, the limit of the expression
is:
0.1667 (i.e. option b is true)
Step-by-step explanation:
We are asked to estimate the limit of the expression:
![\lim_{x \to 3} \dfrac{x-3}{x^2-9}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%203%7D%20%5Cdfrac%7Bx-3%7D%7Bx%5E2-9%7D)
We know that:
![a^2-b^2=(a-b)(a+b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29)
Hence, we could represent it as:
![\lim_{x \to 3} \dfrac{x-3}{x^2-3^2}\\ \\= \lim_{x \to 3} \dfrac{x-3}{(x-3)(x+3)}\\ \\= \lim_{x \to 3} \dfrac{1}{x+3}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%203%7D%20%5Cdfrac%7Bx-3%7D%7Bx%5E2-3%5E2%7D%5C%5C%20%5C%5C%3D%20%5Clim_%7Bx%20%5Cto%203%7D%20%5Cdfrac%7Bx-3%7D%7B%28x-3%29%28x%2B3%29%7D%5C%5C%20%5C%5C%3D%20%5Clim_%7Bx%20%5Cto%203%7D%20%5Cdfrac%7B1%7D%7Bx%2B3%7D)
Since we cancel out the similar terms in the numerator as well as in the denominator.
![\lim_{x \to 3} \dfrac{1}{x+3}=\dfrac{1}{3+3}=\dfrac{1}{6}=0.1667](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%203%7D%20%5Cdfrac%7B1%7D%7Bx%2B3%7D%3D%5Cdfrac%7B1%7D%7B3%2B3%7D%3D%5Cdfrac%7B1%7D%7B6%7D%3D0.1667)
Hence, the limit of the expression
is:
0.1667
Heyy I cant see it :( can u explain more ?
Answer:
13 ft
Step-by-step explanation:
65/5
I have attached an image of the right trapezoid.
Answer:
C: 107°
Step-by-step explanation:
From the image attached, we can see that the right trapezoid has 2 internal angles which are right angles while it has a third angle which is 73°.
Now,we want to find angle WXY.
Sum of angles in a trapezoid is 360°.
Thus;
90 + 90 + 73 + ∠WXY = 360
253 + ∠WXY = 360
∠WXY = 360 - 253
∠WXY = 107°