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3 years ago

6) How many solutions does the system have? y = 5x + 3 and y = -2x + 3

Mathematics

1 answer:

taurus [48]3 years ago

4 0

Step-by-step explanation:

5x + 3 = -2x + 3

7x = 0

x = 0

y = 0 + 3

y = 3

(0, 3)

one solution

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3 years ago

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3 years ago

Yuri thinks that 3/4 is a root of the following function.

sineoko [7]

Given:

The polynomial function is

$q(x)=6x^3+19x^2-15x-28$

Yuri thinks that $\dfrac{3}{4}$ is a root of the given function.

To find:

Why $\dfrac{3}{4}$ cannot be a root?

Solution:

We have,

$q(x)=6x^3+19x^2-15x-28$

If $\dfrac{3}{4}$ is a root, then the value of the function at $\dfrac{3}{4}$ is 0.

Putting $x=\dfrac{3}{4}$ in the given function, we get

$q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28$

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Taking LCM, we get

$q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}$

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Since the value of the function at $\dfrac{3}{4}$ is not equal to 0, therefore, $\dfrac{3}{4}$ is not a root of the given function.

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3 years ago