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3 years ago

Which facts could be applied to simplify this expression? Check all that apply.

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

6 0

Answer:

The answer is B, C, and D. Like terms are terms with all the same variable, so 5x and -x are like terms.

C is correct. If we add -x to 5x, we get 4x. The other numbers remain unchanged because they have no like terms.

D is correct. Applying the rule of like terms, which is that like terms are numbers with the same variable, only add together numbers with the same variable.

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Suppose that IQ scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 12. Using the empirical rul

tankabanditka [31]

Answer:

0.15%

Step-by-step explanation:

We have been given that IQ scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 12. We are asked to find the percentage of IQ scores that are greater than 133 using the empirical rule.

First of all, we will find z-score for given sample score of 133 as z-score tells us a data point is how many standard deviation away from mean.

$z=\frac{x-\mu}{\sigma}$ , where,

$z$ = Z-score,

$x$ = Sample score,

$\mu$ = Mean,

$\sigma$ = Standard deviation.

$z=\frac{133-97}{12}$

$z=\frac{36}{12}$

$z=3$

We know that according to the empirical rule 68% of data lies within one standard deviation of mean, 95% of data lies within two standard deviation of mean and 99.7% of data lies within one standard deviation of mean.

Since 133 is 3 standard deviation above mean, so 0.3% lies above and below 3 standard deviation.

Since we need IQ scores above 133, so we will divide 0.3% by 2 as:

$\frac{0.3\%}{2}=0.15\%$

Therefore, 0.15% of IQ scores are greater than 133.

4 0

4 years ago

The Miller family visited Mama's kitchen and ordered 4 hamburgers and 3 medium fries and paid $17.35. James ordered a medium dri

Lady_Fox [76]

$x-the\ cost\ of\ a\ hamburger\\y-the\ cost\ of\ a\ medium\ friest\\z-the\ cost\ of\ a\ medium\ drink\\\\ \left\{\begin{array}{ccc}4x+3y=17.35\\x+y+z=6.09&\to z=6.09-x-y\\2x+y+z=9.34\end{array}\right\\ \left\{\begin{array}{ccc}4x+3y=17.35\\2x+y+6.09-x-y=9.34\end{array}\right\\\left\{\begin{array}{ccc}4x+3y=17.35\\x=9.34-6.09\end{array}\right\\\left\{\begin{array}{ccc}4x+3y=17.35\\x=3.25\end{array}\right$

$\left\{\begin{array}{ccc}4\cdot11.26+3y=17.35\\x=3.25\end{array}\right\\\left\{\begin{array}{ccc}4\cdot3.25+3y=17.35\\x=3.25\end{array}\right\\\left\{\begin{array}{ccc}13+3y=17.35\\x=3.25\end{array}\right\\\left\{\begin{array}{ccc}3y=17.35-13\\x=3.25\end{array}\right\\\left\{\begin{array}{ccc}3y=4.35\\x=3.25\end{array}\right\\\left\{\begin{array}{ccc}y=1.45\\x=3.25\end{array}\right\\$

$\left\{\begin{array}{ccc}x=3.25\\y=1.45\\z=6.09-3.25-1.45\end{array}\right\\\left\{\begin{array}{ccc}x=3.25\\y=1.45\\z=1.39\end{array}\right\\\\\\Answer:\\Hamburger-\$3.25\\Medium\ fries-\$1.45\\Medium\ drink:\$1.39$

7 0

3 years ago

I need this PLEASE NO ONE IS ANSWERING

arsen [322]

Answer:

you havent posted picture or written out the question

6 0

3 years ago

Dorian buys 2 pounds of almonds for $21.98 and 3 pounds of dried apricots for $

arsen [322]

Cost of 2 pounds of almonds = $ 21.98

So, cost of 1 pound will be = $\frac{21.98}{2} = 10.99$