Answer:
the current daily demand of the check processing facility is 8000 units, and a 16 containers is required.
Explanation:
Solution
Given that,
(A) The calculation of delay demand is as follows:
K = (<u>+_</u>) (<u>1 +)</u> C
K = is the number of containers
d = the average delay demand
w = the waiting time per average per unit
p = the average processing time per unit
C = Container quantity
α = safe guard policy variable
Now,
The average processing time = 2/24 * 60 =0.0167
The average waiting time is = 2/24 =0.083
The required number of container = 20 = (0.083 + 0.0167 ) (1 + 0.25) /50
which is
20 * 50 = (0.1) (1.25)
Thus,
1000 / 0.125 = 8000
Now,
The average daily demand is 8000
The next step is to find out how many containers would be needed.
Now,
If there is no waste, it is = 0
The required number of containers will be =
K = 8000 ( 0.083 + 0.0167) ( 1 + 0 )/ 50
= 8000/5= 16 Containers
