U(x) = f(x).(gx)
v(x) = f(x) / g(x)
Use chain rule to find u(x) and v(x).
u '(x) = f '(x) g(x) + f(x) g'(x)
v ' (x) = [f '(x) g(x) - f(x) g(x)] / [g(x)]^2
The functions given are piecewise.
You need to use the pieces that include the point x = 1.
You can calculate f '(x) and g '(x) at x =1, as the slopes of the lines that define each function.
And the slopes can be calculated graphycally as run / rise of each graph, around the given point.
f '(x) = slope of f (x); at x = 1, f '(1) = run / rise = 1/1 = 1
g '(x) = slope of g(x); at x = 1, g '(1) = run / rise = 1.5/ 1 = 1.5
You also need f (1) = 1 and g(1) = 2
Then:
u '(1) = f '(1) g(1) + f(1) g'(1) = 1*2 + 1*1.5 = 2 + 1.5 = 3.5
v ' (x) = [f '(1) g(1) - f(1) g(1)] / [g(1)]^2 = [1*2 - 1*1.5] / (2)^2 = [2-1.5]/4 =
= 0.5/4 = 0.125
Answers:
u '(1) = 3.5
v '(1) = 0.125
Answer:
Step-by-step explanation:
4x/2= -5
4x= -5*2
2x= -5
x= -5/2
5 times amount of people has to be bigger than 2112
5(133+v)≥2112
distribute
665+5v≥2112
minus 665 from both sides
5v≥1447
divide both sides by 5
v≥289.4
yo can't have 0.4 volunterer
v≥290
has to have at least 290 volunteers
Answer:16/1
Step-by-step explanation:
I think you mean y=ab^x.
First, plug in the values of x=2 and y=24 for the first equation, and x=3 and y=48 for the second one:
24 = ab^2
48 = ab^3
divide equation 2 by equation 1:
2 = b^1
or, more simply:
2 = b
now plug b into one of the equations to get "a":
24 = a*2^2
24 = a*4
6 = a
So, the answer is y = 6(2)^x
(I think you need to specify the power of x in your answers)
