Find the rate of change on the table

Which statement represents a battery with no cellphone battery life .

timofeeve [1]

Answer:

The correct answer is choice 3

Step-by-step explanation:

80 - 80 = 0

bruh

5 0

3 years ago

Read 2 more answers

Solve -14-5y >-64 A. Y<10 B.y>-10 C. Y>10 D.y<-10

amm1812

Hello :D

Answer:

A. $Y$

Step-by-step explanation:

First, you add by 14 both sides of an equation.

-14-5y+14>-64+14

Then, simplify by equation.

-64+14=-50

-5y>-50

Multiply -1 both sides.

(-5y)(-1)<(-50)(-1)

5y<50

Divide by 5 both sides of an equation.

5y/5<50/5

Divide numbers from left to right.

50/5=10

y<10 is the correct answer.

Hope this helps you! :D

6 0

2 years ago

What is the image of (9,3) after a dilation by a scale factor of 3 centered at the origin?

sergiy2304 [10]

Answer: (27, 9)

Multiply the original coordinates by the scale factor 3 to get this answer

9*3 = 27

3*3 = 9

This only works if the center of dilation is the origin.

The general rule is $(x,y) \to (kx, ky)$ where k is the scale factor.

7 0

2 years ago

ou decide to bake some cakes. You need 150 g of flour for 12 cakes. How much flour do you need for 30 cakes? g

Brilliant_brown [7]

Short answer: 375 grams

Remark
You only need to set up a direct proportion

Givens
flour for 12 cakes = 150 grams
Number of cakes initially = 12
Amount of flouer for 30 cakes = x
Number of cakes = 30

Proportion
amount flour for 12 cakes / 12 cakes = x / 30

Sub and solve
150 grams / 12 cakes = x / 30 cakes Cross multiply
150 * 30 = 12 *x Multiply the left side.
4500 = 12 x Divide both sides by 12
4500/12 = x
375 grams for 30 cakes. <<<<< Answer

5 0

3 years ago

Evaluate the definite integral using the graph of f(x) (Image included)

Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

$\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}$

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

$\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}$

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

$\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20$

Then by linearity, we have

$\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}$

8 0

2 years ago