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3 years ago

Solve: 1/3(−6q+4)=−1/12(4q+4)

Mathematics

2 answers:

STatiana [176]3 years ago

6 0

Answer:

Combine multiplied terms into a single fraction

13(−6+4)=−112(4+4)

13(−6q+4)=−112(4q+4)\frac{1}{3}(-6q+4)=\frac{-1}{12}(4q+4)31(−6q+4)=12−1(4q+4)

1(−6+4)3=−112(4+4)

1(−6q+4)3=−112(4q+4)\frac{1(-6q+4)}{3}=\frac{-1}{12}(4q+4)31(−6q+4)=12−1(4q+4)

Multiply by 1

Combine multiplied terms into a single fraction

Distribute

Multiply all terms by the same value to eliminate fraction denominators

Cancel multiplied terms that are in the denominator

Distribute

Subtract

161616

from both sides of the equation

Simplify

Add

4q4q4q

to both sides of the equation

Simplify

Divide both sides of the equation by the same term

Simplify

Show less

Solution

Step-by-step explanation:

Fittoniya [83]3 years ago

4 0

Answer:

q=1

Step 1: Simplify both sides of the equation.

Step 2: Add 1/3q to both sides.

Step 3: Subtract 4/3 from both sides.

Step 4: Multiply both sides by 3/(-5).

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4 years ago

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3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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3 years ago

Ples help and ples give derect awnser not a link you will get brainly if u do

slamgirl [31]

Im sorry i don’t know this but you should try photomath, it might help!

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3 years ago