All categories

3 years ago

8. diameter = 4 cm, height = 3.6 cm T2

Mathematics

1 answer:

gayaneshka [121]3 years ago

5 0

I don't know the answer because i don't know the question

if you can simplify the question

You might be interested in

Which is the length of x? 1 7/9 2 1/2 1 1/4 1 3/5

trapecia [35]

Answer:

option D. x = 1 3/5

Step-by-step explanation:

ratio and proportion

4 = x

5 2

X multiply:

5x = 4(2)

5x = 8

x = 8 / 5

x = 1 3/5

5 0

3 years ago

Read 2 more answers

Which ratio is equivlant to 3:4

Crank

Answer:

There is multiple. You didnt give options so heres all of them.

Step-by-step explanation:

6 : 8 9 : 12 12 : 16 15 : 20 18 : 24 21 : 28 24 : 32 27 : 36 30 : 40 33 : 44 36 : 48 39 : 52 42 : 56 45 : 60 48 : 64 51 : 68 54 : 72 57 : 76 60 : 80 63 : 84 66 : 88 69 : 92 72 : 96 75 : 1007 8 : 104 81 : 108 84 : 112 87 : 116 90 : 120 93 : 124 96 : 128 99 : 132 102 : 136 105 : 140 108 : 144 111 : 148 114 : 152 117 : 156 120 : 160 123 : 164 126 : 168 129 : 172 132 : 1761 35 : 180 138 : 184 141 : 188 144 : 192 147 : 196 150 : 200 153 : 204 156 : 208 159 : 2121 62 : 216 165 : 220 168 : 224 171 : 228 174 : 232 177 : 236 180 : 240 183 : 244 186 : 248 189 : 252 192 : 256 195 : 260 198 : 264 201 : 268 204 : 272 207 : 276 210 : 280 213 : 284 216 : 288 219 : 292 222 : 296 225 : 300 228 : 304 231 : 308 234 : 312 237 : 316 240 : 320 243 : 324246 : 328249 : 332252 : 336255 : 340258 : 344261 : 348264 : 352267 : 356270 : 360273 : 364276 : 368279 : 372282 : 376285 : 380288 : 384291 : 388

etc etc

4 0

3 years ago

Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of

zepelin [54]

Answer:

The larger gear will rotate through 156°

Step-by-step explanation:

Arc Length

The arc length S of an angle θ on a circle of radius r is:

$S = \theta r$

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

$\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}$

The arc length of the smaller gear is:

$\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7$

$\displaystyle S_1=\frac{18.5\pi}{3}$

The larger gear rotates the same arc length, so:

$\displaystyle S_2=\frac{18.5\pi}{3}$

$\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}$

Solving for θ2:

$\displaystyle \theta_2=\frac{18.5\pi}{3r_2}$

$\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}$

$\theta_2=2.73\ radians$

$\displaystyle \theta_2=2.73*\frac{180}{\pi}=156$

The larger gear will rotate through 156°

7 0

3 years ago

Suppose for some positive real number aa that (a^(1 /4) ⋅ a ^(1/ 2 )⋅ a ^(1/ 4) 2 = 3.

Grace [21]

Answer:

(a) $a=\frac{3}{2}$

(b) We use the property of exponent that when there is multiplication of two function then there exponent are added

Step-by-step explanation:

We have given expression

$(a^{\frac{1}{4}}a^{\frac{1}{2}}a^{\frac{1}{4}})2=3$

(a) We have to find the value of a

We know the property of exponent that when there is multiplication of two function then there is addition of exponent

So $a^{\frac{1}{4}+\frac{1}{2}+\frac{1}{4}}\times 2=3$

$2a=3$

$a=\frac{3}{2}$

(b) We use the property of exponent that when there is multiplication of two function then there exponent are added

8 0

3 years ago

if the hieght and radius of the cone is tripled then find the ratio of Volume of the new cone and of that of original

solniwko [45]

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=\stackrel{3\times r}{3r}\\
h=\stackrel{3\times h}{3h}
\end{cases}\implies V=\cfrac{\pi (3r)^2(3h)}{3}
\\\\\\
V=\cfrac{\pi (3^2r^2)(3h)}{3}\implies V=\cfrac{\pi (9r^2)(3h)}{3}\implies V=27\left( \cfrac{\pi r^2 h}{3} \right)$

notice the original, and the new one, with the tripled "r" and "h" is just, whatever the original was times 27, namely 27 times as large as the original.

6 0

3 years ago