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3 years ago

HELP MEEEEE PLEASEEEEEE

Mathematics

2 answers:

stich3 [128]3 years ago

5 0

Answer:

Step-by-step explanation:

2x + 1 = 5

2x = 4

x = 2

liberstina [14]3 years ago

5 0

Answer : 11
Explained : Substitute 5 for x. You now have 2(5)+1. 2(5)=10. 10+1=11.

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Is 12ft greater than or less than or equal than 4yds

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Greater Hope this helps

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Does anybody know what 25*10^6 ?

rjkz [21]

Answer:

25000000

Step-by-step explanation

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What is 1/1024 as a negative exponents

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I think its $32^(-2)$

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3 years ago

In a solar system, two comets pass near the sun, which is located at the origin. Comet E is modeled by quantity y plus 16 end qu

Leya [2.2K]

Explanation:

The equation of comet E is given below as

$\frac{(y+16)^2}{400}+\frac{x^2}{144}=1$

The equation of comet H is modelled below as

$\frac{(y+13)^2}{144}-\frac{x^2}{25}=1$

Given, that the Sun is located at the origin.

This is an equation of an ellipse. So, the path traveled by Comet e is an elliptic path.

Comparing with the Standard equation of ellipse: below,we will have

$\frac{(y-k)^2}{b^2}+\frac{(x-h)^2}{a^2}$

Whise center is

$\begin{gathered} center=(h,k) \\ vertices=(h\pm a,0) \end{gathered}$

By comparing coefficient, we will have

$\begin{gathered} a^2=144 \\ a=12 \\ b^2=400 \\ b=20 \\ k=-16 \\ h=0 \\ (h,k)=(0,-16) \end{gathered}$

Hence,

The vertex of comet E will be

$\begin{gathered} (h\pm a,0) \\ (0+12,0),(0-12,0) \\ (12,0),(-12,0) \end{gathered}$

The vertex of comet E is

$(12,0),(-12,0)$

Part C:

It is the foci forboth comets

$\begin{gathered} cometE: \\ c=\sqrt{b^2-a^2} \\ c=\sqrt{400-144} \\ c=\sqrt{256} \\ c=16 \\ \\ For\text{ comet F:} \\ c=\sqrt{a^2-b^2} \\ c=\sqrt{144+25} \\ c=\sqrt{169} \\ c=13 \end{gathered}$

Hence,

The foci will be

$\begin{gathered} (16\pm16,0) \\ cometE \\ (0,0),(32,0) \\ cometF: \\ (13\pm13,0) \\ (0,0),(26,0) \end{gathered}$

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1 year ago

1. Force is a push or a

Black_prince [1.1K]

Answer:

1. C

2.B

Step-by-step explanation:

Force is a push or a pull.. can be a twist too

to make an object move you have to apply force by pushing of pulling the object.

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3 years ago

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