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2 years ago

1. Force is a push or a

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

8 0

Answer:

1. C

2.B

Step-by-step explanation:

Force is a push or a pull.. can be a twist too

to make an object move you have to apply force by pushing of pulling the object.

Anni [7]2 years ago

3 0

No me voy al hospital a la oficina porque yo no tengo ni caso de la casa ni siquiera te quiero mucho

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(a) has no solutions. (b) has infinitely many solutions. (c) has exactly one solution.

grandymaker [24]

Answer and Step-by-step explanation:

Given

ax + by = c

qx + ry = s

(a) the equation has no solutions if a/q = b/r ≠ c/s, when this happens, we say the system of equations has no solution. For example

x + y = 3

x + y = 5

Subtracting first equation from the second we have:

0 = 2 which is impossible.

(b) the equations have infinite solutions if a/q = b/r = c/s, for example

x + y = 2

Subtracting the first equation from the second we have

0 = 0, since this is always true, then it has infinite solutions.

x + y = 2

x – y = 1

Adding the first and second equation we have

2x = 3, we can get x from here and definitely y, so we have just one solution.

6 0

3 years ago

Asha makes a conjecture that the perimeter of a square whose sides are an odd integer is always even. Which choice is the best p

Ivan

Answer: Bottom left corner

Let n be an odd number. Because 4n is a multiple of 2, it is an even number.

============================================

Explanation:

The square has a side length of n, so its perimeter is 4n since n+n+n+n = 4n.

We can rewrite 4n as 2*2n = 2m where m = 2n is an integer. Any number in the form 2*(some integer) is always even. Even numbers always have 2 as a factor.

So whenever it comes to proving something is even, the ultimate goal is to get it into the form 2*(some integer). If we can do this, then the number is even. If not, then the number is odd.

4 0

2 years ago

Read 2 more answers

. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST we first need to find the gradient of ST, using the gradient formula.

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$