Answer:
d 0.5282
Step-by-step explanation:
Given the following :
Probability of getting to the bus on time = 70% = P = probability of success = 0.7
(1 - p) = probability of failure = 0.3
Number of trials(n) = 5 days
Number of sucesses (r) = atleast 4 days : >= 4
This is a binomial probability problem
P(r) = nCr × P^r × (1 - P)^(n - r)
P(X >=4) = P(4) + P(5)
P(4) = 5C4 × (0.7)^4 × (0.3)^1 = 0.36015
P(5) = 5C5 × (0.7)^5 × (0.3)^0 = 0.16807
P(4) + P(5) = 0.36015 + 0.16807 = 0.52822
