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2 answers:
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Question Continuation:
if (a) the books can be arranged in any order?
(b) the mathematics books must be together and the novels must be together?
Answer:
(a) 3628800 ways
(b) 17280 ways
Step-by-step explanation:
Given
Solving (a): In any order
This implies that there is no restriction and the novels, mathematics and biology book are just seen as books.
Total number of books is:
The number of arrangement is:
(b):
If the mathematics books are together, there are 4! different arrangements
If the novels are together, there are 5! different arrangements
Now, there are 3 bundles.
- The mathematics books as 1
- The novels as 1
- The biology book
This can be arranged in 3! ways.
Total number of arrangement is:
Answer:
D
Step-by-step explanation:
There are 9 letters, which contains 2Qs, 3Ls and 4Bs.
If the 9 letters are distinct, the number of permutations they have will be 9!.
! is the factorial sign.
9! = 9*8*7*6*5*4*3*2*1
HOWEVER, we have some identical elements, so we need to get rid of the permutations of the same letters.
Thus we have:
The answer is D