Question

Write an equation in point-slope form for the line through the given point with the given slope. (8, –3); m = -1/4

Answer 1

The point-slope form of a line is:

y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line.

y+3=(-1/4)(x-8)

Answer 2

Answer: $x+4y+4=0[$

Step-by-step explanation:

The point-slope form of a line that passes from point (a,b) has slope m is given by :-

$(y-b)=m(x-a)$

Then , the point-slope form of a line that passes from  point (8, –3) and has slope $m=\dfrac{-1}{4}$ is given by :-

$(y-(-3))=\dfrac{-1}{4)}(x-8)\\\\ 4(y+3)=-1(x-8)\\\\ 4y+12=8-x\\\\ x+4y+4=0$

Hence, the equation in point-slope form for the line through the given point (8, –3) with the given slope $m=\dfrac{-1}{4}$ is  $x+4y+4=0[$