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Zielflug [23.3K]
4 years ago
12

Find all zeros of 2x4 - 5x3 + 53x2 - 125x + 75=0

Mathematics
1 answer:
ser-zykov [4K]4 years ago
5 0
Retire zero la bour li dan trou fess to pu ggnr bon

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Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 p
Aleks [24]

Answer:

11000 JY.

Step-by-step explanation:

According to today's exchange rate

1 US dollar = 110 JY

100 US dollars = 100 * 110 JY

You should get 11000 JY.

Pick the answer that is closest to this exchange rate.

8 0
2 years ago
The largest major arc is:<br> MHJ<br> JMG<br> GNM<br> HLI
crimeas [40]

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the correct answer is HLI

7 0
2 years ago
What type of slope does
sukhopar [10]

Answer:

B

Step-by-step explanation:

The equation is in slope-intercept form, so the slope is the coefficient of x. Since the coefficient of x is negative, so is the slope.

4 0
1 year ago
Which is the best estimate of each percent? 24% of 398
Bingel [31]

To find the 24% of 398, multiply 398 by 24 and divide it by 100:

398\cdot\frac{24}{100}=95.52

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4 0
1 year ago
Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20

So, she makes mistake in step 2 as the z terms are not being cancelled.

6 0
3 years ago
Read 2 more answers
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