Let x be unknown number which should be added to numbers 1, 11, 23 to get geometric progression. Then numbers 1 + x, 11 + x, 23 + x are first three terms of geometric progression.

Hence,

$b_1=1+x\\ \\b_2=11+x\\ \\b_3=23+x$

and

$b_2=b_1\cdot q\Rightarrow 11+x=(1+x)q\\ \\b_3=b_2\cdot q\Rightarrow 23+x=(11+x)q$

Express q:

$q=\dfrac{11+x}{1+x}=\dfrac{23+x}{11+x}$

Solve this equation. Cross multiply:

$(11+x)^2=(1+x)(23+x)\\ \\121+22x+x^2=23+x+23x+x^2\\ \\121+22x=23+24x\\ \\22x-24x=23-121\\ \\-2x=-98\\ \\2x=98\\ \\x=49$

5 0

3 years ago

A refrigerator box measures 11 feet by 6 feet by 6 feet Sam decides to fill up the box three-fourths with trash how much space w

IRINA_888 [86]

Answer:

297 feet

Step-by-step explanation:

11 × 6 × 6 = 396

396 × 3/4= 297 ft

3 0

3 years ago

Jarod bought 8 yards of ribbon. He needs 200 inches to use to make curtains. How many inches of ribbon does he have?

frosja888 [35]

288 inches is needed

4 0

3 years ago

Find f (3) +g(1) – g(3) =

pantera1 [17]

Sorry I don’t know the answer hope you find one bye halleluja

3 0

3 years ago