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denis23 [38]
3 years ago
11

SOLVE FOR X TO THE NEAREST TENTH

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

x = 8.8

Step-by-step explanation:

First, you have to solve the side length for the smaller triangle.

c= \sqrt{ a^{2} +b^{2} }\\c= \sqrt{5^{2}+4^{2}  } \\\\c=\sqrt{25+16} \\c=\sqrt{41} \\c= 6.4\\

Now for the bigger square.

c= \sqrt{ a^{2} +b^{2} \\}    \\c = \sqrt{6.4^{2} +6^{2} } \\c= \sqrt{40.96+36} \\c= \sqrt{ 76.96}\\c= 8.77\\

Rounded to the nearest tenth = 8.8

https://g.co/kgs/dg245M

I use this for my pythagorean theorem questions

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11111nata11111 [884]

Answer:

9 questions x 4 answers per question

9x4= 36

6 0
3 years ago
Read 2 more answers
What does -3(n+5)=12 equal
Reil [10]

Answer:

n= -9

Step-by-step explanation:

-3 ( n+5 ) = 12

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6 0
4 years ago
Helppppppppp pleaseeee Someoneeeee pleaseeee I neeed
Stella [2.4K]

Answer:

The minimum value of f(x) is 2

Step-by-step explanation:

  • To find the minimum value of the function f(x), you should find the value of x which has the minimum value of y, so we will use the differentiation to find it
  • Differentiate f(x) with respect to x and equate it by 0 to find x, then substitute the value of x in f(x) to find the minimum value of f(x)

∵ f(x) = 2x² - 4x + 4

→ Find f'(x)

∵ f'(x) = 2(2)x^{2-1} - 4(1)x^{1-1} + 0

∴ f'(x) = 4x - 4

→ Equate f'(x) by 0

∵ f'(x) = 0

∴ 4x - 4 = 0

→ Add 4 to both sides

∵ 4x - 4 + 4 = 0 + 4

∴ 4x = 4

→ Divide both sides by 4

∴ x = 1

→ The minimum value is f(1)

∵ f(1) = 2(1)² - 4(1) + 4

∴ f(1) = 2 - 4 + 4

∴ f(1) = 2

∴ The minimum value of f(x) is 2

7 0
3 years ago
Which statement correctly identifies a local minimum of the graphed function? Over the interval [–3, –2], the local minimum is 0
marta [7]

Answer:

C.

Step-by-step explanation:

As we can see on the graph C is our answer.

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4 years ago
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Y= 13 over 10x + 2 is the answer. The most important thing to remember when finding the slope of the line is RISE over RUN. When you rise, you go up or down. When you run, you go right or left. Think of RISE over RUN as a fraction.

You find two points on the line and you count up/down a certain amount of spaces, and right/left a certain amount of spaces to go from one point to the other point.

In this equation, we could use the point on the y-axis and the last point we see on the graph located at (10,15). You count up/down vertically first until you reach the horizontal line that the point is on. Then, you count the amount of spaces horizontally it takes you to reach the point. In this problem, you move up 13 spaces, and move to the right 10 spaces. This as a fraction will be 13 over 10, because we rose 13 spaces and we ran 10 spaces to get to our second point. The y-intercept will be the only number that is on the y-axis, which is 2.
7 0
4 years ago
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