Which equation represents a line that passes through (–9, –3) and has a slope of –6?

Mathematics

1 answer:

tatiyna3 years ago

6 0

Answer:

y+3 = -6(x+9)

Step-by-step explanation:

m(x-x1)= (y-y1)

-6[x-(-9)] = [y-(-3)]

-6(x+9) = y+3

.....

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Ahh help plss!! thank u

AnnZ [28]

Basically you’re multiplying them both
(x^3 + 2x - 1)(x^4 - x^3 + 3)

so you need to make sure you multiply each one, if you do it right, you should end up with
x^7 - x^6 + 3x^3 + 2x^5 - 2x^4 + 6x -x^4 +x^3 -3

simplify by adding like terms
x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3

your answer would be the third option

4 0

3 years ago

How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$