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allochka39001 [22]
2 years ago
12

HELPPPPPP PLEASE I AM STRUGLING]

Mathematics
1 answer:
atroni [7]2 years ago
6 0

10 is the answer

why are you struggling

so simple

<h2><em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>❣❣</u></em><em><u> </u></em></h2>

<em><u>Mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em>

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8 more than 5 times a number is -27
Romashka [77]

8 + 5n = -27

5n = -35

n = -7

7 0
3 years ago
Would really appreciate it... will mark brainliest
d1i1m1o1n [39]

Exponential growth would include, A = 20,000(1.08)^t, A=40(30), P=1700(1.07).

Decay would include, A=80(1/2)^t, A= 1600(.8), P=1700(.93)

Hope this helps.

5 0
3 years ago
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Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?
Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ =  sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0
3 years ago
How can you compare ratios to solve a problem?
Sindrei [870]
“To use proportions to solve ratio word problems, we need to follow these steps:
Identify the known ratio and the unknown ratio.
Set up the proportion.
Cross-multiply and solve.
Check the answer by plugging the result into the unknown ratio.”
I hope this helps.
6 0
3 years ago
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WILL GIVE LOTS OF POINTS !!! PLEASE HELP<br> Question:<br><br> Find the quotient.
geniusboy [140]

Answer:

1. Simplify the expression.

x2 + 3

2. Simplify the expression.

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3 years ago
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