A fair die would have 6 sides,
Therefore, 6 different numbers has a probability to appear.
Thus, any number has 1/6 chance to appear.
Since you want a specific sequence to occur,
4 results would be (1/6)^4
Therefore the probability is 1/54
Answer:
Yes No Yes should be right
let me know if wrong
Step-by-step explanation:
There is a percent formula that can solve all of these...
is / of = % / 100
what percent is 32 out of 80...
% = x...because this is what we r looking for
is = 32
of = 80
now sub into the formula
32/80 = x/100
cross multiply because this is a proportion
(80)(x) = (32)(100)
80x = 3200
x = 3200/80
x = 40......so 32 is 40% of 80
12 is 60% of what number...
is = 12
% = 60
of = x
sub
12/x = 60/100
cross multiply
(60)(x) = (12)(100)
60x = 1200
x = 1200/60
x = 20.....so 12 is 60% of 20
what is 30% of 70
is = x
% = 30
of = 70
x / 70 = 30/100
(100)(x) = (30)(70)
100x = 2100
x = 2100/100
x = 21.....so 21 is 30% of 70
what is 40% of 75
is = x
% = 40
of = 75
x / 75 = 40/100
(100)(x) = (75)(40)
100x = 3000
x = 3000/100
x = 30....so 30 is 40% of 75
the pic
what is 40% of 35
is = x
% = 40
of = 35
x/35 = 40/100
(100)(x) = (35)(40)
100x = 1400
x = 1400/100
x = 14.....so 14 is 40% of 35....14 goes in the box
The answer to your problem is going to be that there is a total of 432 seats in each movie area. you get this by multiplying 18 and 24 together. this is because there is 24 seats in each of the 18 rows. it is the same as finding the area of a rectangle, length * width.