We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
M5 is the same as m1 so it's 75°
Answer:
False
Step-by-step explanation:
y = -3× - 2
4 = -3(2) - 2
4 = -6 - 2
4 = -8
<span>-x^2 + x-1=0 divide by (-) </span><span><span>
</span>
</span><span>x^2-x+1=0 </span><span><span>
</span>
</span><span>x=1/2(+-) root of (1/2)^2-1 </span><span><span>
</span>
</span><span>x=1/2(+-) root of (1/4)-1 </span><span><span>
</span> </span><span><span>
</span></span><span>x=1/2(+-) root of (1/4)-1 </span>
<span>
x=1/2(+-) root of (1/4)-((4*1)/4) </span>
<span>
x=1/2(+-) root of (-3/4)
</span>
<span>which has not answers, because we can not take a root of negatives numbers</span>
Answer:
24 and 25
Step-by-step explanation:
From given, we have,
7 square = 49
Let the first positive number be = x
And the second consecutive positive number is = x+1
x + (x + 1) = 49
2x + 1 = 49
2x = 49 - 1
2x = 48
x = 24
the first number x = 24
the second consecutive number x+1 = 24 + 1 = 25
Thus, 7 square = 24 + 25 (the sum of two consecutive positive numbers.)
