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frutty [35]
2 years ago
14

The initial population of a town is 2500, and it grows with a doubling time of 10 years. What will the population be in 8 years?

Mathematics
1 answer:
alisha [4.7K]2 years ago
4 0
2500x0.80=2000 so i think it would be 2000 in 8 years

or if youre adding the 2000 to the already existing 2500 then it would be 4500.
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Answer:

Step-by-step explanation:

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

Considering the 36-month loan,

T = 36 months = 36/12 = 3 years

P = $15000

R = 6.5%

Therefore

I = (15000 × 6.5 × 3)/100

I = 292500/100

I = $2925

Considering the 48-month loan loan,

T = 48 months = 48/12 = 4 years

P = $15000

R = 7.5%

Therefore

I = (15000 × 7.5 × 4)/100

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4 0
2 years ago
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goldenfox [79]

For this case we must find the product of two mixed numbers:

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So, we have:

\frac {10} {3} * \frac {21} {4} = \frac {10 * 21} {3 * 4} = \frac {210} {12} = \frac {105} {6} = \frac {35} {2}

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\frac {35} {2} = 17 \frac {1} {2}

Answer:

17 \frac {1} {2}

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3 years ago
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Answer:1/3

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8 0
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Answer:

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Step-by-step explanation:

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6 0
2 years ago
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lesantik [10]

Answer: See explanation

Step-by-step explanation:

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