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Serga [27]
3 years ago
14

3. The Earth's core is about the size of

Chemistry
1 answer:
san4es73 [151]3 years ago
3 0
C. The United States
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C8H10N4O2 is the chemical formula for caffeine. List the 3 remaining elements in caffeine and how many atoms of that element are
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What happens when water is added to sodium bicarbonate
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Sodium bicarbonate (or baking soda) will cause both exothermic and endothermic reactions when added to water. It becomes either unstable or stable carbonic acid, which will eventually become CO2. The reaction would be exothermic is when H2CO3 (Carbonic Acid unstable) is formed and endothermic is when CO2 is.
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Which of the following was not a contribution by Niels Bohr? Quantum energy emissions. The charge of an electron. There is a rel
borishaifa [10]

Out of the given options, the charge of an electron was not contributed by Neils Bohr.

Answer: Option 2

<u>Explanation: </u>

The electron's charge was determined by using oil drop experiments performed by Millikan. While Neil Bohr suggested that electrons are rotating in discrete energy levels termed as orbits.

The hydrogen model of Neil Bohr dealt with the quantum energy emission when electron excite from higher energy level to lower energy level. He also stated that there is a relationship between the outer shell and the chemical properties of elements.

So, the second option that is the charge of an electron is not contributed by Bohr as it was contributed by Millikan.

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3 years ago
Main group elemants are arranged in _______ groups
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3 0
4 years ago
In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) H2O (g) CO2
jolli1 [7]

Answer: K_{eq} at  the temperature of the experiment is 0.56.

Explanation:

Moles of  CO = 0.35 mole

Moles of  H_2O = 0.40 mole

Volume of solution = 1.00 L

Initial concentration of CO = \frac{0.35mol}{1.00L}=0.35M

Initial concentration of H_2O = \frac{0.40mol}{1.00L}=0.40M

Equilibrium concentration of CO = \frac{0.19mol}{1.00L}=0.19M

The given balanced equilibrium reaction is,

                      CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.          0.35 M         0.40 M                  0 M        0M

    At eqm. conc.     (0.35-x) M   (0.40-x) M   (x) M      (x) M

Given:  (0.35-x) = 0.19

x= 0.16 M

The expression for equilibrium constant for this reaction will be,

K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}  

Now put all the given values in this expression, we get :

K_{eq}=\frac{0.16\times 0.16}{(0.35-0.16)\times (0.40-0.16)}

K_{eq}=\frac{0.16\times 0.16}{(0.19)\times (0.24)}=0.56

Thus K_{eq} at  the temperature of the experiment is 0.56.

3 0
3 years ago
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