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sweet [91]
3 years ago
14

What are five compounds that contain carbon and what is one use for them?​

Chemistry
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

there are a lot of compounds that contain Carbon

for Example

Methane CH4 / is used primarily as fuel to make heat and light

Ethanol CH3OH / is used extensively as a solvent in the manufacture of varnishes and perfumes

Benzene C6H6 / is a major part of gasoline, It's used to make plastics.

Propane C5H12 /  used for space and water heating, for cooking, and as fuel for engine

Hexane C6H14 / used in the production of glues for shoes, leather products, and roofing

Explanation:

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High levels of moisture are contained within an air mass.

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3. Calculate the percent yield of silver chromate if 0.455 grams of silver chromate are produced
andrezito [222]

The answer is in the photo.

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Measurements are commonly recorded as
kaheart [24]

Kilometers, Meters and centimeters if metric

Feet, inches, yards and miles if customary ( u.s.)

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Ivahew [28]

Answer: skeleton equation

Explanation:

7 0
3 years ago
Determine the mass (in grams) of 8.02 x 1024 atoms of mercury (Hg).
Virty [35]
<h3>Answer:</h3>

2670 g Hg

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation: </h3>

<u>Step 1: Define</u>

8.02 × 10²⁴ atoms Hg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 8.02 \cdot 10^{24} \ atoms \ Hg(\frac{1 \ mol \ Hg}{6.022 \cdot 10^{23} \ atoms \ Hg})(\frac{200.59 \ g \ Hg}{1 \ mol \ Hg})
  2. Divide/Multiply:                                                                                               \displaystyle 2671.42 \ g \ Hg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2671.42 g Hg ≈ 2670 g Hg

3 0
3 years ago
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