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Natali5045456 [20]
2 years ago
15

What is the value of cos Tan

Mathematics
1 answer:
marysya [2.9K]2 years ago
3 0
The answer would be D
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Determine if x+3 is a factor of -3x^3+6x^2+6x+9. How do u know
krek1111 [17]
By the factor theorem, if x + 3 is a factor of f(x) = -3x^3 + 6x^2 + 6x + 9, then f(-3) = 0
f(-3) = -3(-3)^3 + 6(-3)^2 + 6(-3) + 9 = -3(-27) + 6(9) - 18 + 9 = 81 + 54 - 9 = 126.

Therefore, x + 3 is not a factor of the given function
6 0
2 years ago
How do i factor the coefficent out of a variable, such as 2.4n+9.6 and -6z+12
ANEK [815]
You are factoring one or more linear expressions (but are not factoring variables).

2.4n+9.6 can be divided by 2.4 and then the result mult. by 2.4:

2.4n+9.6 = 2.4 [ n + 4 ]

Also:  -6z+12= 6 [ -z + 2 ]  Here I have simplified linear functions but factoring out common constant coefficients (not variables).
4 0
3 years ago
I having trouble on number 7
labwork [276]
The answer is c=1/4p Solve for C by simply multiplying 1/4 x 8 and you get 2, 1/4 x 12 and you get 3, so on and so forth
5 0
3 years ago
Which choice is a graph of the solution set for 12 - X &lt; 8?<br> Pleaseeeee helpppppp NUMBER 14
yarga [219]

Answer:

B

Hope this helps!

explanation:

we solve the inequality and to do that we must first subtract 12 from both sides, which gets us -x<-4, then we divide both sides by -1, which gives us x>4, since we have to flip the sign when we divide by a negative. when we graph this, there will be a circle around 4 and the arrow pointing to the right, since it's greater than.

7 0
3 years ago
2a + 4b + c =5 <br> x =-2 <br><br> a - 4b = -6<br> y=1
cricket20 [7]
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10 [2] b-c=15 [3] a-2b+c=-5 Equations Simplified or Rearranged :<span><span>  [1] 2a + c = -10 </span><span>  [2] - c + b = 15 </span><span>  [3] a + c - 2b = -5 </span></span>Solve by Substitution :

// Solve equation [3] for the variable  c  
 

<span> [3] c = -a + 2b - 5 </span>

// Plug this in for variable  c  in equation [1]

<span><span>  [1] 2a + (-a +2?-5) = -10 </span><span>  [1] a = -5 </span></span>

// Plug this in for variable  c  in equation [2]

<span><span>  [2] - (-? +2b-5) + b = 15 </span><span>  [2] - b = 10 </span></span>

// Solve equation [2] for the variable  ?  
 

<span> [2] ? = b + 10 </span>

// Plug this in for variable  ?  in equation [1]

<span><span>  [1] (? +10) = -5 </span><span>  [1] 0 = -15 => NO solution </span></span><span>No solution</span>
3 0
3 years ago
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