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Arlecino [84]
2 years ago
9

Find the value of SU

Mathematics
1 answer:
sineoko [7]2 years ago
3 0

Answer:

A

Step-by-step explanation:

yw

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The perimeters of the square and the triangle shown below are equal. What is the value of x?
Rudiy27
Perimeter is the sum of all the sides. So we can set up an equation:

\sf 3x+1+3x+1+3x+1+3x+1=2x+8+x+8+4x+2

Now solve for 'x', combine like terms:

When it comes to terms with variables it's just like normal addition but we keep the variable:

\sf 3x+3x+3x+3x=12x
\sf 2x+x+4x=7x

So we have:

\sf 12x+1+1+1+1=7x+8+8+2

Add:

\sf 12x+4=7x+18

Subtract 7x to both sides:

\sf 5x+4=18

Subtract 4 to both sides:

\sf 5x=14

Divide 5 to both sides:

\boxed{\sf x=2.8}
8 0
3 years ago
What is the solution for 3x-(2+4x)
Ivenika [448]
The answer is - 7x-2
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3 years ago
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Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

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3 years ago
Put the fractions in order from smallest to largest.<br> 5/12<br> 2/3<br> 5/6
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2/3 = 8/12
5/6 = 10/12

10/12, 8/12, 5/12

5/6, 2/3, 5/12 is the order
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3 years ago
Francis decides to take 32 swords from his friend Dead pool. If the quantity taken by Francis is only 3/7 of the number of sword
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If you’re rounding up it would be 75. But if you round down 74
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3 years ago
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