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Inga [223]
4 years ago
7

Sam stores manure for his farm in a rectangular box. The length of the box is 7 feet, The width is 9 inches, and the height is 6

inches. Each bag of Manure he bought contains 2.625 cubic feet of manure. How many bags of manure will fill the ox completely?
Mathematics
2 answers:
ANEK [815]4 years ago
8 0
It should only be able to hold 1 bag of manure
vlada-n [284]4 years ago
5 0
<h2>Answer:</h2>

The number of  bags of manure which will fill the box completely is:

                                  One

<h2>Step-by-step explanation:</h2>

We know that the volume of rectangular box with length(l), width(w) and height(h) is given by:

Volume=lwh

Here we have:

l=7 feet

w=9 inches=0.75 feet

( since, 12 inch=1 feet

Hence, 1 inch=1/12 feet )

and

h=6 inches=0.5 feet

Hence, the volume of the rectangular box is:

Volume= 7×0.75×0.5

i.e.

Volume=2.625 cubic feet.

Now, the number of bags of manure that will fill the box completely is:

Ratio of volume of box to Volume of 1 bag of  manure

= 2.625/2.625

=1

Hence, only one bag of manure could be fit into the box.

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dybincka [34]

6582 dollars, divided equally amoung 32 employees.

Let's use multiplication to guess and get a close answer, it's a little easier than division:

32 x 100 = 3200 (but we need about twice this amount)

32 x 200 = 6400 (we still have 182 more dollars left over)

So now we know that each employee gets about 200 dollars, but let's get more specific.

Let's try 32 x 5, which equals 160. We can't "fit" any more in, because all that's left is 22 dollars.

We have 32 x 200 and 32 x 5, which together is 32 x 205 (= 6560) and the closest we can get to $6582 if we're splitting all of the money evenly.

Each employee should recieve $205.

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Step-by-step explanation:

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4 years ago
Solve the system...................​
AlexFokin [52]

Answer:

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Step-by-step explanation:

We have the following system of linear equations

\left \{{{x+6y=2} \atop {5x+4y=36}} \right.

To solve the system multiply the first equation by -5 and then add it to the second equation.

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-----------------

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