Answer:
1994
Step-by-step explanation:
9514 1404 393
Answer:
(d) 5a²
Step-by-step explanation:
![\displaystyle\sqrt[3]{125a^6}=\sqrt[3]{5^3a^6}=\sqrt[3]{(5a^2)^3}=\boxed{5a^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B125a%5E6%7D%3D%5Csqrt%5B3%5D%7B5%5E3a%5E6%7D%3D%5Csqrt%5B3%5D%7B%285a%5E2%29%5E3%7D%3D%5Cboxed%7B5a%5E2%7D)
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The applicable rules of exponents are ...
(a^b)^c = a^(bc)
∛a = a^(1/3)
Answer:
The correct answer is NO. The best price to be charged is $3.75
Step-by-step explanation:
Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.
⇒ 4P = 30 - Q
⇒ P = 
The current price of the necklace $10.
Revenue function is given by R = P × Q =
× ( 30Q -
)
To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.
=
× ( 30 - 2Q) = 0
⇒ Q = 15.
The second order derivative is negative showing that the value of Q is maximum.
Therefore P at Q = 15 is $3.75.
Thus to maximize revenue the price should be $3.75.
Answer
24
Explanation
4! This is read as 4 factorial.
It means;
4! = 4×3×2×1
= 24