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Verdich [7]
2 years ago
14

What is the approximate diameter of a sphere with a volume of 900 cm³? I will give Brainliest

Mathematics
1 answer:
jenyasd209 [6]2 years ago
6 0

Answer:

Step-by-step explanation:

4/3pi r3=900

pi r3= 675

r3=675*7/22

r3=214

r is about 6 so d=2r=12

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When did pollution first became an issue?
pickupchik [31]

Answer:

1994

Step-by-step explanation:

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3 years ago
Find the cube root.
nignag [31]

9514 1404 393

Answer:

  (d)  5a²

Step-by-step explanation:

  \displaystyle\sqrt[3]{125a^6}=\sqrt[3]{5^3a^6}=\sqrt[3]{(5a^2)^3}=\boxed{5a^2}

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  (a^b)^c = a^(bc)

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4 0
3 years ago
the crowd at a sporting event is estimated to be 2,500 people. the exact attendance is 2,486 people. what is the percentage erro
Verdich [7]

Answer:

0.56%

Step-by-step explanation:

Percentage error

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5 0
3 years ago
Read 2 more answers
Currently, the demand equation for necklaces is Q = 30 – 4P. The current price is $10 per necklace. Is this the best price to ch
barxatty [35]

Answer:

The correct answer is NO. The best price to be charged is $3.75

Step-by-step explanation:

Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.

⇒ 4P = 30 - Q

⇒ P = \frac{30-Q}{4}

The current price of the necklace $10.

Revenue function is given by R = P × Q = \frac{1}{4} × ( 30Q - Q^{2})

To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.

\frac{dR}{dQ} =  \frac{1}{4} × ( 30 - 2Q) = 0

⇒ Q = 15.

The second order derivative is negative showing that the value of Q is maximum.

Therefore P at Q = 15 is $3.75.

Thus to maximize revenue the price should be $3.75.

6 0
3 years ago
Evaluate 4!.<br><br> a.) 4<br> b.) 12<br> c.) 24
Gwar [14]

Answer

24


Explanation

4! This is read as 4 factorial.


It means;

4! = 4×3×2×1

= 24

6 0
3 years ago
Read 2 more answers
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