Answer:
(x+3)(x+4)(x-4)
x+2 and x-3 are not factors but x-4 is
Step-by-step explanation:
let's factor it :)
x^3 + 3x^2 - 16x -48
first we will factor this:
x^3 + 3x^2
x^2(x + 3)
then factor the second part :
- 16x - 48
-16(x + 3)
so now,
x^2(x + 3) - 16(x + 3)
factor out x+3
(x+3)(x^2 - 16)
factor x^2 - 16
(x+3)(x+4)(x-4)
That would be the area of a circle of radius 12 miles
= pi r^2 = 452.4 square miles to nearest tenth.
X2-2x-35=0x2-7x+5x-35=0x(x-7)+5(x-7)=0(x-7)(x+5)=0x-7=0 or x+5=0x=7 or x=-5 Check: x=7 ,LHS = 49-14-35 =0 =RHS x=-5, LHS = 25+10-35 =0=RHSAns: x=7 or x=-5
<span><span>x2</span>−x−12=0</span>
It’s D that is the answer
