Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
-9 21/50
Step-by-step explanation:
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Answer:
352cm²
Step-by-step explanation:
The shape is a cuboid and it has 6 faces, and the opposite faces are equal, so I calculate 3 different faces and multiplied it by 2 to give me the total surface area. Therefore, total surface area = the addition of all the surface areas in the shape. And to get each surface area, you have find the area of each of the 6 faces, and add them together, to give you the total surface area.
Hello there!
8m² - 4(7m³ + 5n²)
You wanna start by using the distributive property
=8n² - (-4)(7m³) + (-4)(5n²)
= 8n² - 28m³ - 20n²
= -28m³ - 12m²
