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zhuklara [117]
3 years ago
7

Which of the following is a proper fraction 7/6 4/3 1/2 3/3

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
1/2 because 7/6 & 4/3 are improper fractions(fractions that have a higher numerator than a denominator) and 3/3 should just be written as 1.
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Whats another way to write 300 70 5/10 8/100?
Triss [41]
I do not think we need to rewrite the first two numbers in the given above because they are already the simplest forms of themselves being whole numbers. However, the third number may be rewritten as 1/2 by dividing both numerator and denominator by 5 and the last one as 2/25 by dividing both numerator and denominator by 4. 
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3 years ago
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How do if find y=-3x+10 and y=-2+6?
Len [333]
Yep the other one is right it is (4,-2)
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3 years ago
The age of trees in a forest is known to be approximately normal with an average age of 40 years and a standard deviation of 10
Keith_Richards [23]

Answer: D. -0.6

Step-by-step explanation:

Z score formula= x-mean/ SD

34-40/10= -3/5= -0.6

6 0
3 years ago
the number of hours h that it takes for ice to malt varies inversely with the temperature t it takes 3hours for a piece of ice t
Reptile [31]

Answer:

Step-by-step explanation:

Formula

h = k/temp

Givens

h = 4 hours

t = 45 degrees

Solution

3 = k / 45                  Multiply both sides by 45

3*45 = k

k = 135

Problem

what happens when h = 4 hours?

h = 4

k = 135

temp = ?

4 = 135 / temp       Multiply both sides by temp

4temp = 135          Divide by 4

temp = 135 / 4

temp = 33.75

Note that as the time went up, the temperature came down

6 0
2 years ago
A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte
Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that \mu = 48, \sigma = 12

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 48}{12}

Z = 2.5

Z = 2.5 has a p-value of 0.9938.

0.9938*100% = 99.38%.

A customer who sends 78 messages per day would be at 99.38th percentile.

8 0
3 years ago
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