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Fed [463]
3 years ago
11

What is the solution set to 8(2x - 3) s 20 - 4X?

Mathematics
1 answer:
Zolol [24]3 years ago
8 0

Answer:

d

Step-by-step explanation:

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In Mrs. Marsh's algebra class, 30 of the 36 students took the Chapter 4 test, and their mean score was $72 \%$. The next day the
hammer [34]

The new class mean of the given information in percent  = 73%

<h3>What is algebra?</h3>

One of the many branches of mathematics is algebra. Algebra, which is a common thread throughout practically all of mathematics, is broadly defined as the study of mathematical symbols and the rules for manipulating these symbols in formulas.

<h3>According to the information :</h3>

A total of 2160 points would be earned if 30 students obtained an average grade of 72.

= 30 x 72

= 2160

If six students had an average of 78, their total points would be 6 x 78, or 468.

= 6 x 78

= 468

points are the result of adding the points from both groups.

2160 + 468

= 2628

An average of 73 is obtained by dividing 2628 by 36.

It represents a 73% proportion.

To know more about Algebra expression visit:

brainly.com/question/14083225

#SPJ4

I understand that the question you are looking for is:

In Mrs. Marsh's algebra class, 30 of the 36 students took the Chapter 4 test, and their mean score was $72 \%$. The next day the other six students took the test and their mean score was $78 \%$. What is the new class mean? Express your answer as a percent.

7 0
2 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
Suppose cot(theta) = 5/12, where pi &lt; theta &lt; 3pi/2. What is sin(theta)?
trasher [3.6K]

Answer:

- 12 /13

Step-by-step explanation:

Given that:

Cot(θ) = 5 /12 ;

Recall ; cot θ = 1 / tan θ ; tan θ = sin θ / cos θ

Hence ;

tan θ = 1 / cot θ

tan θ = 1 ÷ (5 / 12)

tan θ = 1 * 12 /5 = 12/5

Tan θ = opposite / Adjacent = 12 /5

Sin θ = opposite / hypotenus

Hypotenus = √(opposite² + adjacent²)

Hypotenus = √12² + 5²

Hypotenus = √(144 + 25)

Hypotenus = √169

Hypotenus = 13

Hence,

Sin θ = opposite / hypotenus = 12 / 13

pi < theta < 3pi/2 lies in the 3rd quadrant ; SinΘ will be negative ;

Sin θ = - 12 /13

6 0
3 years ago
Read 2 more answers
Samatha received $500 as a graduation present and decides to invest it in an account that is
Elan Coil [88]

Answer:

Step-by-step explanation:

m= month

3÷100= 0.03

0.03×500=<u>$15</u>

$15/m

$15×5×12=$900

$500-$900= <u> </u>

<u>Answer: -$400</u>

6 0
4 years ago
The exam scores on a statistics final exam are normally distributed with a mean of 140 points out of 200 and standard deviation
kumpel [21]

Answer:0.78%

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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