We have that
solution is
x <-10 or x>=25
for
x < -10
the solution is the interval (-∞, -10)
and
for
x>=25
the solution is the interval [25,∞)
therefore
the solution for
x <-10 or x>=25
is
(-∞, -10) ∪ [25,∞)
<span>the solution is any value of x less than -10 or greater than or equal to 25</span>
Answer: (9ab^2+c^3)(9ab^2-c^3)
Step-by-step explanation:
81a^2b^4-c^6
(9ab^2)^2-(c^3)^2
(9ab^2+c^3)(9ab^2-c^3)
Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤
Answer:
- -28y^4 - 7y^3 + 62y^2 + 5y - 30
Step-by-step explanation:
<u>Opening the parenthesis and simplifying by combining like terms:</u>
- (6 - y - 4y^2)(-5 + 7y^2) =
- 6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
- -30 + 42y^2 + 5y - 7y^3 +20y^2 -28y^4 =
- -28y^4 - 7y^3 + 62y^2 + 5y - 30
Answer:
123123 3213123 12312 dasdsd aw dasd sda asdasd
Step-by-step explanation:
