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2 years ago

Please Help Me !!! Thanks whoever answers it

Mathematics

1 answer:

Korvikt [17]2 years ago

7 0

IT IS B I DID THE WORK U CAN TEUST ME PLS PARK ME BRALIEST AND LIKE THANK U SO MUCH

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Which number is NOT in the solution set of the inequality x>-15?

Ipatiy [6.2K]

Answer:

Step-by-step explanation:

if x has to be greater than -15 and -20 = x than its not true because -20 isn't greater than -15

5 0

3 years ago

Read 2 more answers

Select all expressions that represent a correct solution to the equation 6(x+4)=20

Sergeeva-Olga [200]

Answer:

D. 20 ÷ 6 − 4

E. 1/6(20 − 24)

F. (20−24) ÷ 6

Step-by-step explanation:

6(x + 4) = 20

6(x) + 6(4) = 20

6x + 24 = 20

- 24 - 24

6x = -4

/6 /6

x = -4/6 or x = -2/3

D. 20 ÷ 6 − 4

20/6 - 4

20/6 - 24/6

-4/6 = -2/3

E. 1/6(20 − 24)

1/6(-4)

-4/6 = -2/3

F. (20 − 24) ÷ 6

- 4 / 6

-4/6 = -2/3

Hope this helps!

3 0

2 years ago

Use sigma notation to represent the following series for the first 12 terms. 2 +(-8) +32 + (-128) + .

Marysya12 [62]

$\displaystyle\sum_{i = 1}^{12} 2(-4)^{i-1}$

7 0

3 years ago

Read 2 more answers

What are the x- and y-coordinates of point C, which partitions the directed line segment from A to B into the ratio 5:8? Round t

Fantom [35]

Answer:

(1.2, –4.7)

Step-by-step explanation:

Since in the question it is mentioned that on the plane of coordinate, a line is made from point A (7,-2) to point B(-8,-9)

Also, the ratio of A to B is 5:8

Based on this, the x and y coordinates at point C is

$= [\frac{5\times (-8) + 8\times 7}{5 + 8} , \frac{5\times (-9) + 8\times -2}{5 + 8}]\\\\= [\frac{16}{3}, \frac{-61}{13}]$

= (1.2, –4.7)

Hence, the x and y coordinates of point C is (1.2, –4.7)

Therefore the last option is correct

4 0

2 years ago

Solve (x-3)^2 = 5 HELP ASAP!!! Please!! :(

Bas_tet [7]

Answer:

Answer is option d 

Step-by-step explanation:

$given \: expression \: is \: {(x - 3)}^{2} = 5 \\ {x}^{2} - 6x + 9 = 5 \\ subtracting \: 5 \: on \: both \: sides \: we \: get \\ {x}^{2} - 6x + 4 = 0 \\ on \: solving \: the \: quadratic \: equation \: by \\ \: completing \: square \: method \\ {x}^{2} - 6x = - 4 \\ adding \: {3}^{2} on \: both \: sides \: w e\: get \\ {x}^{2} - 6x + {3}^{2} = {3}^{2} - 4 \\ {(x - 3)}^{2} = 5 \\ x - 3 + = \sqrt{5} \\ x = \sqrt{5 } + 3$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

5 0

2 years ago