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Dvinal [7]
3 years ago
11

What so the mean median and range for 39,82,74,96,64,52,74

Mathematics
1 answer:
3241004551 [841]3 years ago
3 0
Mean: 68.71
Median: 74
Range: 57
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The length of a rectangle is three times the width. The perimeter of the rectangle is at most 112cm. Which inequality models the
EleoNora [17]

Answer:

8x⩽112

Step-by-step explanation:

Width of the rectangle (in centimeters) = x

Therefore, the lenght of the rectable is 3x (in centimeters).  

The perimeter of the rectangle (in centimeters) is : 2x+2*3x=2x+6x=8x.

The perimeter of the rectangle is at most 112cm, therefore, 8x⩽112.

8 0
3 years ago
Solve the following using substitution method
Wewaii [24]

Solution :

2a + 2b = 7    ...1)

4a + 3b = 12   ...2)

In equation, 1)

a = (7 - 2b)/2   ...3)

Putting value of a in equation 2) we get :

4 × (7 - 2b)/2  + 3b = 12

2( 7 - 2b ) + 3b = 12

14 - 4b + 3b = 12

b = 2

Putting value of b in 3) we get :

a = ( 7 - 2×2)/2

a = 3/2 = 1.5

Now,

2x - 3y = 16   ...5)

x + 2y = -6    ...6)

x = -6 - 2y

Putting above value of x in eq 5) , we get :

2( -6 - 2y ) - 3y = 16

-12 - 4y - 3y = 16

7y = -28

y = -4

x = -6 - ( 2× -4 )

x = 2

Hence, this is the required solution.

6 0
3 years ago
For all real numbers b and c such that the product of
qwelly [4]

Answer:

E: b/3+3

Step by step:

3 C= b

C + 3 = b/3 + 3                     (Adding 3 to both sides)

Answer: E: b/3 + 3

Hope this helps

3 0
3 years ago
Plzzzzzz helppppp asappppp <br> ***will mark brainliest *****
Vanyuwa [196]

i am not sure but it think its 6 root 2

6 0
3 years ago
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
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