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Dvinal [7]
2 years ago
11

What so the mean median and range for 39,82,74,96,64,52,74

Mathematics
1 answer:
3241004551 [841]2 years ago
3 0
Mean: 68.71
Median: 74
Range: 57
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The makers of Mini-Oats cereal have an automated packaging machine that is set to fill boxes with 24 ounces of cereal. At variou
Butoxors [25]

Answer:

1. A is the null hypothesis. The null hypothesis is the statement in which everything is operating as expected; nothing unusual is going on.

2. C is the alternative hypothesis. The problem says that you are looking to see whether or not the machine is filling with an average of 24 ounces, so it could be over or under filling. B only accounts for under filling.

Step-by-step explanation:

3 0
3 years ago
In what shape are the lateral faces of a pyramid?
Helga [31]
<span><span>SphereA sphere is the set of all points in space that are a fixed distance from a common point called the center.</span><span>Pyramids<span>A three-dimensional shape with one polygonal base and lateral faces the shape of triangles that meet at a common vertex, called the apex

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5 0
3 years ago
23454793142528293623939303905058585838385
Tomtit [17]
Yes this is the best kind of question
4 0
3 years ago
Read 2 more answers
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
if 62% percent of people voted in a community of about 55,200 eligible voters how many people were registerd
solniwko [45]
62% of 55,200...turn ur percent to a decimal..." of " means multiply
0.62(55,200) = 34,224 <==

although, just because u r registered, does not mean u vote.
6 0
3 years ago
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