What so the mean median and range for 39,82,74,96,64,52,74

The length of a rectangle is three times the width. The perimeter of the rectangle is at most 112cm. Which inequality models the

EleoNora [17]

Answer:

8x⩽112

Step-by-step explanation:

Width of the rectangle (in centimeters) = x

Therefore, the lenght of the rectable is 3x (in centimeters).

The perimeter of the rectangle (in centimeters) is : 2x+2*3x=2x+6x=8x.

The perimeter of the rectangle is at most 112cm, therefore, 8x⩽112.

8 0

3 years ago

Solve the following using substitution method

Wewaii [24]

Solution :

2a + 2b = 7 ...1)

4a + 3b = 12 ...2)

In equation, 1)

a = (7 - 2b)/2 ...3)

Putting value of a in equation 2) we get :

4 × (7 - 2b)/2 + 3b = 12

2( 7 - 2b ) + 3b = 12

14 - 4b + 3b = 12

b = 2

Putting value of b in 3) we get :

a = ( 7 - 2×2)/2

a = 3/2 = 1.5

Now,

2x - 3y = 16 ...5)

x + 2y = -6 ...6)

x = -6 - 2y

Putting above value of x in eq 5) , we get :

2( -6 - 2y ) - 3y = 16

-12 - 4y - 3y = 16

7y = -28

y = -4

x = -6 - ( 2× -4 )

x = 2

Hence, this is the required solution.

6 0

3 years ago

For all real numbers b and c such that the product of

qwelly [4]

Answer:

E: b/3+3

Step by step:

3 C= b

C + 3 = b/3 + 3 (Adding 3 to both sides)

Answer: E: b/3 + 3

Hope this helps

3 0

3 years ago

Plzzzzzz helppppp asappppp <br> ***will mark brainliest *****

Vanyuwa [196]

i am not sure but it think its 6 root 2

6 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago