Question

Please anyone I’ll mark as a branlist

Answer 1

Answer:

the first option is the answer, r = √6

Step-by-step explanation:

$hypotenuse = \sqrt{opposite {}^{2} + adjacent {}^{2} }$

hypotenuse = q = √12

adjacent = p = √6

opposite = r

substitute the values into the hypotenuse formula

$q = \sqrt{r {}^{2} + p {}^{2} }$

$\sqrt{12} = \sqrt{r {}^{2} + ( \sqrt{6} ) {}^{2} }$

$( \sqrt{12} ) {}^{2} = r {}^{2} +6$

$12 = r {}^{2} + 6$

$12 - 6 = r {}^{2}$

$6 = r {}^{2}$

$\sqrt{6} = r$

$r = \sqrt{6}$