Sorry for the way it came out but the Answer:
2
x
+
5
=
43
∘
3
x
−
10
=
47
∘
Explanation:
A complementary angles means angles that add up to
90
degrees. The two angles given in the question are complementary angles.
So
Our first angle
(
2
x
+
5
)
plus the second angle
(
3
x
−
10
)
is equal to
90
degrees
(
2
x
+
5
)
+
(
3
x
−
10
)
=
90
Now we solve for
x
, first we add up the like terms
2
x
+
3
x
+
5
−
10
=
90
5
x
−
5
=
90
Add
5
to both sides
5
x
=
95
Divide both sides by
5
we get
x
=
19
Now and after we find
x
we substitute it to get our two angles
2
x
+
5
=
2
(
19
)
+
5
=
43
∘
3
x
−
10
=
3
(
19
)
−
10
=
47
∘
Hope it helps :)
Step-by-step explanation:
<h2>Length = 11</h2><h2>Width = 6</h2>
The area of a rectangle is 66 ft^2:
L * W = 66
Length of the rectangle is 7 feet less than three times the width:
L = 3W-7
Substitute L in terms of W:
(3W-7) * W = 66
Factorise the equation:
3W^2 -7W = 66
3W^2 - 7W - 66 = 0
Factors of 66 =
1 66, 2 33, 3 22, 6 11
(3W + 11) (W - 6) = 0
Solve for W:
3W + 11 = 0
3W = 11
W = 3/11
W - 6 = 0
W = 0 + 6
W = 6
Using the original equation, find L:
L = 3W-7
L = 3(6)-7
L = 18-7
L = 11
L * W = 66
11 * 6 = 66
I believe the answer is C
I would say that the correct answer is D. because y is always the numerator while x is the denominator for the equation y2 - y1/x2 - x1 which means if there is two y's or two x's on the same line you subtract the second one from the first one. If there is only one y and/or x and the other is 0 on the same line, it stays at y or x without subtracting y2 - y1 or x2 - x1.
Since b is on the y coordinate and -a is on the x coordinate, you would make it b/a while -a is gonna be a positive since the lines are going up and to the right. Now, since c is the y coordinate and d is the x coordinate, make C the numerator and d the denominator since y is always the numerator and x is the denominator for these parallel line figures on the graph and the equation will be equaled to the fraction to the other fraction for parallel lines.
So, your answer would be D. b/a = c/d
Hope this helps, and is correct!
<em>~ ShadowXReaper069</em>
