Observe the sequences below. I. 3, 6, 9, 12, ... II. 3, 9, 27, 81, III. 2, 4, 8, 16, ... IV. 3, 5, 7, 9, Which of these are geom
Sholpan [36]
Observe the sequences below. I. 3, 6, 9, 12, ... II. 3, 9, 27, 81, III. 2, 4, 8, 16, ... IV. 3, 5, 7, 9, Which of these are geometric sequences? III only O Il and me II and IV O I and
Here are three ways where There could be equal rows
3*12=36
4*9=36
6*6=36
Answer:
1. 7/9
2. 7/16
3. 3/7
4. 123/125
Step-by-step explanation:
1. Simplify the following:
2/9 + 5/9
2/9 + 5/9 = (2 + 5)/9:
(2 + 5)/9
2 + 5 = 7:
Answer: 7/9
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2. Simplify the following:
3/4 - 5/16
Put 3/4 - 5/16 over the common denominator 16. 3/4 - 5/16 = (4×3)/16 - 5/16:
(4×3)/16 - 5/16
4×3 = 12:
12/16 - 5/16
12/16 - 5/16 = (12 - 5)/16:
(12 - 5)/16
12 - 5 = 7:
Answer: 7/16
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3. Simplify the following:
6/7×1/2
6/7×1/2 = 6/(7×2):
6/(7×2)
6/2 = (2×3)/2 = 3:
Answer: 3/7
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4. Rewrite the decimal number as a fraction with 1 in the denominator
0.984=0.984/1
Multiply to remove 3 decimal places. Here, you multiply top and bottom by 10^3 = 1000
(0.984/1)×(1000/1000)= 984/1000
Find the Greatest Common Factor (GCF) of 984 and 1000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 8,
(984/8) = 123
(1000/8) = 125
Therefore
X=123/125
In conclusion,
Answer: 0.984=123/125
Answer:
188 units cubed
Step-by-step explanation:
Answer:
the first one is right, the second is less than or equal to (the second to last sign) and the last one is greater than or equal to( the last sign)
Step-by-step explanation: