The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is
seconds
So, the time required for 200 wing beat
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...

So, the time required for one wing beat is 5 milliseconds.
Answer:
what are you asking for
Step-by-step explanation:
Answer:
I believe the answer is 1800
Step-by-step explanation:
120000 * 0.065 = 7800
120000 * 0.08 = 9600
9600 - 7800 = 1800
That would be on the 5th week. There were 18 students that attended (D.)
Hope this helped!
Answer:
Lower than 50%
Step-by-step explanation: