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svetlana [45]
3 years ago
15

Please Help! Urgent!!

Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0

= ( {p}^{  \frac{1}{2}  } )^{3}  \times  \sqrt{p ^{6} }

= ( {p}^{  \frac{3}{2}  } ) \times  {p ^{ \frac{1}{2} × 6} }

= ( {p}^{  \frac{3}{2}  } ) \times  {p ^{ 3} }

= ( {p})^{  \frac{3}{2} + 3}

= ( {p})^{  \frac{3 + 3}{2}}

= ( {p})^{  \frac{9}{2}}

Ray Of Light [21]3 years ago
3 0

Answer:

Step-by-step explanation:

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uysha [10]
Joaquin is the x amount

6 0
3 years ago
Read 2 more answers
What is the probability that a junior non-Nutrition major and then a sophomore Nutrition major are chosen at random? Express you
aleksandr82 [10.1K]

Answer:

0.0032

The complete question as seen in other website:

There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.

Step-by-step explanation:

Total number of in a nutrition class = 111 students

To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.

Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)

Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)

There are 13 number of junior non-Nutrition major

Pr (j non-N) = 13/111

Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)

Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)

There are 3 number of sophomore Nutrition major

Pr (S N-major) = 3/111

The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111

= 39/12321

= 0.0032

7 0
4 years ago
Please helppppp!!!!!
saul85 [17]

Answer:

right angle

Step-by-step explanation:

sorry if its wrong

5 0
3 years ago
En una hoja de papel cuyo perímetro es de 96 centímetros, se quiere imprimir un volante de manera que el área impresa sea un rec
elixir [45]

Answer:

El perímetro de la región impresa es 72 cm y su área es 288 cm².  

Step-by-step explanation:

1. Tenemos el perímetro de la hoja de papel:

P₁ = 96 cm = 2l₁ + 2a₁  (1)  

Como sabemos el margen superior, inferior, izquierdo y derecho podemos encontrar la relación entre el largo y ancho del rectángulo interno (región impresa) con el largo (l) y ancho (a) del rectángulo externo (hoja de papel):      

l_{2} = l_{1} - (m_{s} + m_{i}) = l_{1} - (3 cm + 2 cm) = l_{1} - 5 cm  (2)            

a_{2} = a_{1} - (m_{d} + m_{iz}) = a_{1} - (2 cm + 5 cm) = a_{1} - 7 cm   (3)    

El perímetro del rectángulo interno es:

P_{2} = 2l_{2} + 2a_{2}    (4)

Introduciendo la ecuación (2) y (3) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2(l_{1} - 5 cm) + 2(a_{1} - 7 cm) = 2l_{1} + 2a_{1} - 10 cm - 14 cm = 96 cm - 24 cm = 72 cm  

Por lo tanto el perímetro del rectángulo interno (región impresa) es 72 cm.

 

2. Ahora para encontrar el área rectángulo interno debemos encontrar el largo y ancho del mismo, sabiendo que:

l_{2} = 2a_{2}     (5)

Introduciendo (5) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2*2a_{2} + 2a_{2} = 6a_{2}

a_{2} = \frac{P_{2}}{6} = \frac{72 cm}{6} = 12 cm

l_{2} = 2a_{2} = 2*12 cm = 24 cm

Entonces el área es:

A_{2} = l_{2}*a_{2} = 12 cm*24 cm = 288 cm^{2}

Por lo tanto el área del rectágulo interno (región impresa) es 288 cm².      

Espero que te sea de utilidad!  

7 0
3 years ago
The perimeter of a rectangle is 254 cm. Its length is 55 cm. What is the width of the rectangle with a variable?
Elanso [62]

Answer:

Rectangle w=72

Step-by-step explanation:

Rectangle

Solve for 

width

w

=

72

cm

l

Length

cm

P

Perimeter

cm

5 0
3 years ago
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